v^(2/3)+v^(1/3)=6

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Solution for v^(2/3)+v^(1/3)=6 equation:


v in (-oo:+oo)

v^(2/3)+v^(1/3) = 6 // - 6

v^(2/3)+v^(1/3)-6 = 0

t_1 = v^(1/3)

1*t_1^2+1*t_1^1-6 = 0

t_1^2+t_1-6 = 0

DELTA = 1^2-(-6*1*4)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)-1)/(1*2) or t_1 = (-25^(1/2)-1)/(1*2)

t_1 = 2 or t_1 = -3

t_1 = -3

v^(1/3)+3 = 0

1*v^(1/3) = -3 // : 1

v^(1/3) = -3

( -3 < 0 i 1/3 in (0:1) ) => v naleu017Cy do O

t_1 = 2

v^(1/3)-2 = 0

1*v^(1/3) = 2 // : 1

v^(1/3) = 2

v^(1/3) = 2 // ^ 3

v = 8

v = 8

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